C# 에서 multipart/form-data로 파일 업로드하는 예제.
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public class FormFile
{
public string Name { get; set; }
public string ContentType { get; set; }
public string FilePath { get; set; }
public Stream Stream { get; set; }
}
public class RequestHelper
{
public static string PostMultipart(string url, Dictionary<string, object> parameters)
{
string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
byte[] boundaryBytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n");
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
request.ContentType = "multipart/form-data; boundary=" + boundary;
request.Method = "POST";
request.KeepAlive = true;
request.Credentials = System.Net.CredentialCache.DefaultCredentials;
if (parameters != null && parameters.Count > 0)
{
using (Stream requestStream = request.GetRequestStream())
{
foreach (KeyValuePair<string, object> pair in parameters)
{
requestStream.Write(boundaryBytes, 0, boundaryBytes.Length);
if (pair.Value is FormFile)
{
FormFile file = pair.Value as FormFile;
string header = "Content-Disposition: form-data; name=\"" + pair.Key + "\"; filename=\"" + file.Name + "\"\r\nContent-Type: " + file.ContentType + "\r\n\r\n";
byte[] bytes = System.Text.Encoding.UTF8.GetBytes(header);
requestStream.Write(bytes, 0, bytes.Length);
byte[] buffer = new byte[32768];
int bytesRead;
if (file.Stream == null)
{
// upload from file
using (FileStream fileStream = File.OpenRead(file.FilePath))
{
while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
requestStream.Write(buffer, 0, bytesRead);
fileStream.Close();
}
}
else
{
// upload from given stream
while ((bytesRead = file.Stream.Read(buffer, 0, buffer.Length)) != 0)
requestStream.Write(buffer, 0, bytesRead);
}
}
else
{
string data = "Content-Disposition: form-data; name=\"" + pair.Key + "\"\r\n\r\n" + pair.Value;
byte[] bytes = System.Text.Encoding.UTF8.GetBytes(data);
requestStream.Write(bytes, 0, bytes.Length);
}
}
byte[] trailer = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "--\r\n");
requestStream.Write(trailer, 0, trailer.Length);
requestStream.Close();
}
}
using (WebResponse response = request.GetResponse())
{
using (Stream responseStream = response.GetResponseStream())
using (StreamReader reader = new StreamReader(responseStream))
return reader.ReadToEnd();
}
}
}
|
cs |
호출 시 예제
설정된 변수 값은 예제여서 임의로 작성
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string result = string.Empty; // 전송 후 결과값
result = RequestHelper.PostMultipart(
"http://www.naver.com", new Dictionary<string, object>()
{
{
"uploadFile0", new FormFile()
{
Name = string.Format("{0}_{1}_0",blbd_no, pstg_no), -- 보내지는 파일명
ContentType = "application/pdf", -- 파일 타입
FilePath = LocalFullPath -- 로컬파일경로
}
}
}
);
|
cs |
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[C#] GET, POST 전송 및 처리(HttpWebRequest) (0) | 2019.01.17 |
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